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The problem asks for the area of a photo frame measuring \( \frac{1}{4} \, \text{m} \times \frac{1}{4} \, \text{m} \).

To find the area of a rectangle, we use the formula:

\[
\text{Area} = \text{length} \times \text{width}
\]

Substituting the given dimensions:

\[
\text{Area} = \frac{1}{4} \times \frac{1}{4} = \frac{1}{16} \, \text{m}^2
\]

Thus, the area of the photo frame is \( \frac{1}{16} \, \text{m}^2 \).

Would you like more details on the steps involved or have any questions?

Here are five related questions to explore further:
1. What is the perimeter of a frame measuring \( \frac{1}{4} \, \text{m} \times \frac{1}{4} \, \text{m} \)?
2. How would the area change if the dimensions were doubled?
3. What is the area of a square with side length \( \frac{1}{2} \, \text{m} \)?
4. How do you find the area of a square if one side is given in decimal form (e.g., 0.25 meters)?
5. What is the area of a rectangle with dimensions \( 2 \, \text{m} \times \frac{1}{4} \, \text{m} \)?

**Tip**: To multiply fractions, multiply the numerators together and the denominators together!

What is the area of a photo frame measuring 1/4 m by 1/4 m?

Learn how to calculate the area of a photo frame with dimensions 1/4 m by 1/4 m. This problem focuses on basic geometry concepts and the multiplication of fractions. Suitable for students in Grades 4-6.

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