The problem asks for the area of a composite figure, which is made up of a rectangle and two right triangles. Here's how we can solve it:

Step-by-Step Solution:

1. Area of the rectangle:

   • The dimensions of the rectangle are given as $27 \, \text{ft} \times 11 \, \text{ft}$.
   • The area $A_{\text{rect}}$ is calculated by multiplying the base by the height: $A_{\text{rect}} = 27 \, \text{ft} \times 11 \, \text{ft} = 297 \, \text{square feet}$

2. Area of the two right triangles:

   • Each triangle has a base of $7 \, \text{ft}$ and a height of $13 \, \text{ft} - 11 \, \text{ft} = 2 \, \text{ft}$.
   • The area of one triangle $A_{\text{tri}}$ is: $A_{\text{tri}} = \frac{1}{2} \times 7 \, \text{ft} \times 2 \, \text{ft} = 7 \, \text{square feet}$
   • Since there are two triangles, the total area of the triangles is: $A_{\text{total triangles}} = 2 \times 7 \, \text{square feet} = 14 \, \text{square feet}$

3. Total area of the composite figure:

   • Now, add the areas of the rectangle and the two triangles: $A_{\text{total}} = 297 \, \text{square feet} + 14 \, \text{square feet} = 311 \, \text{square feet}$

Final Answer:

The area of the composite figure is $311 \, \text{square feet}$.

Would you like more details or have any questions?

Here are some related questions you might find helpful:

1. How do you calculate the area of irregular shapes?
2. What is the formula for the area of a trapezoid?
3. How do you break down composite figures into simpler shapes?
4. How do you determine the height of a right triangle in composite shapes?
5. How would the area change if the dimensions of the rectangle were different?

Tip: Always ensure the units of measurement are consistent when calculating areas or perimeters.