Math Problem Statement

Calculate the areas for the given composite shapes.

Solution

Let's analyze each of the shapes and calculate their areas. I'll address them one by one:

Top Row:

  1. Shape 1 (Left - Trapezoid/Composite Shape)

    • Given: 4 yd width, height is split into 3 yd and 2 yd.
    • It appears to be a trapezoid, or a combination of a rectangle and a triangle.
    • The area provided is 16 yd², which matches.
  2. Shape 2 (Middle - Rectangle with Semi-Circle)

    • Given: 12 ft width, 9 ft height, and a semi-circle with a radius of 4 ft.
    • The area is calculated as:
      • Area of the rectangle: 12×9=10812 \times 9 = 108 ft²
      • Area of the semi-circle: 12πr2=12π(4)2=8π25.1\frac{1}{2} \pi r^2 = \frac{1}{2} \pi (4)^2 = 8\pi \approx 25.1 ft²
      • Total area: 108+25.1133.1108 + 25.1 \approx 133.1 ft².
    • The area provided is 133.1 ft², which matches.
  3. Shape 3 (Right - Triangle)

    • Given: Base = 16 ft, Height = 8 ft.
    • Area calculation: Area=12×Base×Height=12×16×8=64 ft2\text{Area} = \frac{1}{2} \times \text{Base} \times \text{Height} = \frac{1}{2} \times 16 \times 8 = 64 \text{ ft}^2
    • The area box is empty, so 64 ft² is the correct answer.

Bottom Row:

  1. Shape 4 (Left - Trapezoid)

    • Given: Height = 14 m, bases are 14 m and 7 m.
    • Area calculation: Area=12×(14+7)×14=12×21×14=147 m2\text{Area} = \frac{1}{2} \times (14 + 7) \times 14 = \frac{1}{2} \times 21 \times 14 = 147 \text{ m}^2
  2. Shape 5 (Middle - Rectangle with Semi-Circle)

    • Given: Width = 11 cm, semi-circle with radius 4 cm.
    • Area calculation:
      • Area of the rectangle: 11×4=4411 \times 4 = 44 cm²
      • Area of the semi-circle: 12π(4)2=8π25.1\frac{1}{2} \pi (4)^2 = 8\pi \approx 25.1 cm²
      • Total area: 44+25.169.144 + 25.1 \approx 69.1 cm².
  3. Shape 6 (Right - Composite Shape: Triangle + Semi-Circle)

    • Given: Triangle base = 9 in, height = 19 in, semi-circle radius = 9 in.
    • Area calculation:
      • Area of the triangle: 12×9×19=85.5\frac{1}{2} \times 9 \times 19 = 85.5 in²
      • Area of the semi-circle: 12π(9)2=40.5π127.2\frac{1}{2} \pi (9)^2 = 40.5\pi \approx 127.2 in²
      • Total area: 85.5+127.2212.785.5 + 127.2 \approx 212.7 in².

Final Answers:

  1. 16 yd²
  2. 133.1 ft²
  3. 64 ft²
  4. 147 m²
  5. 69.1 cm²
  6. 212.7 in²

Would you like further explanations or details about any of these calculations?

Here are five related questions for further practice:

  1. How would the area change for the triangle if its height was increased by 50%?
  2. What is the area of a circle with a radius of 5 meters?
  3. If the trapezoid's bases were swapped in the first shape, would it affect the area calculation?
  4. How do you calculate the area of a quarter-circle?
  5. What is the perimeter of the rectangle and semi-circle composite shape?

Tip: When dealing with composite shapes, calculate the area of each part separately and then add them up to find the total area.

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Math Problem Analysis

Mathematical Concepts

Area Calculation
Composite Shapes
Geometry

Formulas

Area of a rectangle: width × height
Area of a triangle: 1/2 × base × height
Area of a trapezoid: 1/2 × (base1 + base2) × height
Area of a circle: π × radius^2

Theorems

Area calculation for composite shapes

Suitable Grade Level

Grades 8-10