The problem given is about the movement of the minute hand of a clock.

Problem Breakdown

1. The length of the minute hand (jarum menit) is given as $14 \, \text{cm}$.
2. The minute hand moves for 30 minutes.
3. We need to find the distance traveled by the tip of the minute hand in this time.

Solution

1. Since the clock is circular, the movement of the minute hand over 30 minutes represents a half-circle because 30 minutes is half of the full 60 minutes (one complete revolution).

2. The distance traveled by the tip of the minute hand in a half-circle can be calculated using the formula for the circumference of a circle.

   The formula for the circumference of a full circle is: $C = 2 \pi r$ For half of the circumference (a half-circle), it becomes: $\text{Half-Circle Distance} = \pi r$

3. Substituting $r = 14 \, \text{cm}$: $\text{Distance} = \pi \times 14 = 14\pi \approx 43.96 \, \text{cm}$

Answer

The length of the path traveled by the tip of the minute hand in 30 minutes is approximately $43.96 \, \text{cm}$.

Would you like a further explanation or have any questions?

Related Questions

1. What is the total distance traveled by the minute hand in one hour?
2. How would the answer change if the length of the minute hand was 20 cm?
3. What is the formula to calculate the distance traveled for any angle moved by the clock hand?
4. How does the speed of the hour hand compare with the minute hand on a clock?
5. What is the angular speed of the minute hand in degrees per minute?

Tip

In problems involving circular motion, always check if the distance can be found by determining a fraction of the circle’s circumference.