Great! Since the point \( P \) is at the origin \((0, 0)\), the transformation for a 90° clockwise rotation simplifies. 

For any point \((x, y)\), the rotation formula around the origin is:
\[
(x', y') = (y, -x)
\]

Let's apply this to each vertex of the triangle \( \triangle A'B'C' \).

### Step-by-Step Transformation:
- **Vertex \( A' \):** Suppose \( A' \) has coordinates \((x_{A'}, y_{A'})\).
  \[
  A''(x_{A''}, y_{A''}) = (y_{A'}, -x_{A'})
  \]

- **Vertex \( B' \):** Suppose \( B' \) has coordinates \((x_{B'}, y_{B'})\).
  \[
  B''(x_{B''}, y_{B''}) = (y_{B'}, -x_{B'})
  \]

- **Vertex \( C' \):** Suppose \( C' \) has coordinates \((x_{C'}, y_{C'})\).
  \[
  C''(x_{C''}, y_{C''}) = (y_{C'}, -x_{C'})
  \]

### Applying this to the Image:
If you can provide the coordinates for the vertices \( A' \), \( B' \), and \( C' \) from the image, I can calculate the new coordinates for the rotated triangle.

Would you like to extract the coordinates from the image, or do you need help with that? Alternatively, if you can provide those coordinates directly, I'll compute the new positions for the vertices.

Explore how to apply the rotation formula for a 90° clockwise rotation around the origin to point P at coordinates (0,0). This solution demonstrates step-by-step transformations for vertices A', B', and C' of triangle triangle A'B'C' using the given rotation formula. Suitable for students in Grades 9-12 studying geometry and coordinate geometry.

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