Math Problem Statement

How much must you deposit each year into your retirement account starting now and continuing through year 15.00 if you want to be able to withdraw $80000 per year forever, beginning 28.00 years from now? Assume the account earns interest at 9.00% per year. (Round the final answer to three decimal places.)

The amount to be deposited is determined to be $ .

Solution

To solve this, we'll break the problem down into two parts: first, how much you need to have in your account at year 28 to make withdrawals of $80,000 per year forever, and second, how much you need to deposit each year for the next 15 years to accumulate that amount.

Step 1: How much should be in the account at year 28?

You want to make withdrawals of $80,000 per year forever, starting from year 28. This is a perpetuity, which can be calculated using the formula for the present value of a perpetuity:

PV=PMTrPV = \frac{PMT}{r}

Where:

  • PVPV is the present value (the amount you need at year 28).
  • PMTPMT is the annual payment ($80,000).
  • rr is the interest rate (9% or 0.09).

Substituting the values:

PV=80,0000.09=888,888.89PV = \frac{80,000}{0.09} = 888,888.89

So, you need $888,888.89 in your account at year 28 to be able to withdraw $80,000 per year forever.

Step 2: How much to deposit each year for the next 15 years?

Now, we need to figure out how much to deposit each year for the next 15 years to accumulate $888,888.89 by year 28. The future value of an annuity formula will be used for this:

FV=P×(1+r)n1rFV = P \times \frac{(1 + r)^n - 1}{r}

Where:

  • FVFV is the future value ($888,888.89).
  • PP is the annual deposit (this is what we're solving for).
  • rr is the interest rate (0.09).
  • nn is the number of years of deposits (15 years).

Rearranging the formula to solve for PP:

P=FV×r(1+r)n1P = \frac{FV \times r}{(1 + r)^n - 1}

Substituting the known values:

P=888,888.89×0.09(1+0.09)151P = \frac{888,888.89 \times 0.09}{(1 + 0.09)^{15} - 1}

Now, let's compute this step by step:

P=88,888.889(1.09)151P = \frac{88,888.889}{(1.09)^{15} - 1} P=88,888.8893.64241P = \frac{88,888.889}{3.6424 - 1} P=88,888.8892.6424P = \frac{88,888.889}{2.6424} P33,694.760P \approx 33,694.760

So, you must deposit approximately $33,694.760 per year for 15 years.

Final Answer:

The amount to be deposited each year is $33,694.760.


Would you like further details on the calculations, or have any specific questions on how to approach these types of problems?

Here are some related questions to expand your understanding:

  1. How does the length of time affect the amount you need to deposit each year?
  2. What would happen if the interest rate were higher or lower than 9%?
  3. How would the solution change if the annual withdrawal amount were $100,000 instead of $80,000?
  4. What are the tax implications of withdrawals in a retirement account like this?
  5. How does compounding frequency (e.g., quarterly vs. annually) affect this calculation?

Tip: Understanding the concept of perpetuities and annuities is key in retirement planning problems. The present value of a perpetuity allows you to determine how much you need at the beginning, and then the future value of an annuity helps you figure out how much to save annually.

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Math Problem Analysis

Mathematical Concepts

Annuities
Perpetuities
Future Value
Present Value

Formulas

PV = PMT / r (Present Value of a Perpetuity)
FV = P × ((1 + r)^n - 1) / r (Future Value of an Annuity)

Theorems

Present Value of Perpetuity
Future Value of Annuity

Suitable Grade Level

Grades 11-12 (High School or College)