The point $(- \sqrt{2}/2, - \sqrt{2}/2)$ on the unit circle is located in the third quadrant. This corresponds to an angle where both the sine and cosine values are negative.

For this point, both the x-coordinate (cosine) and the y-coordinate (sine) are equal to $- \sqrt{2}/2$, which matches the reference angle of $45^\circ$.

Since the point is in the third quadrant, we use the formula for finding the angle in this quadrant: $\theta = 180^\circ + \text{reference angle}$

Thus, the angle is: $\theta = 180^\circ + 45^\circ = 225^\circ$

Therefore, the angle that intersects the unit circle at the point $(- \sqrt{2}/2, - \sqrt{2}/2)$ is $225^\circ$.

Would you like more details or have any questions?

Here are 5 related questions:

1. What is the reference angle for a point in the fourth quadrant?
2. How can you determine which quadrant a point on the unit circle lies in?
3. What are the sine and cosine values for $45^\circ$?
4. How do we calculate angles for other quadrants using reference angles?
5. What are the coordinates of the point corresponding to $315^\circ$?

Tip: To find the angle based on coordinates on the unit circle, always identify the quadrant and the reference angle first.