Math Problem Statement

Zueinander windschiefe Geraden zeichnen - Gegeben sind die zwei Geraden g und h. a) Bestimmen Sie die Spurpunkte der Geraden und zeichnen Sie die Geraden in ein Schrägbild eines Koordinatensystems ein. b) Zeigen Sie, dass die beiden Geraden g und h windschief zueinander sind, auch wenn dies in der Zeichnung nicht so aussieht.

Solution

This exercise involves two lines, gg and hh, in space. We are given their parametric forms and asked to:

  1. Determine the intercept points of these lines with the coordinate planes and then draw them in an oblique view.
  2. Prove that the lines gg and hh are skew (non-parallel and non-intersecting).

Step-by-Step Solution

Given Data

The parametric equations for the lines are:

  • Line g:x=(334)+s(112)g: \vec{x} = \begin{pmatrix} 3 \\ 3 \\ 4 \end{pmatrix} + s \cdot \begin{pmatrix} 1 \\ 1 \\ 2 \end{pmatrix}
  • Line h:x=(223)+t(011)h: \vec{x} = \begin{pmatrix} 2 \\ 2 \\ 3 \end{pmatrix} + t \cdot \begin{pmatrix} 0 \\ 1 \\ -1 \end{pmatrix}

Part (a): Determine the Intercept Points (Spurpunkte)

To find the intercepts with the coordinate planes (where one of xx, yy, or zz is zero), we set each coordinate equal to zero in turn and solve for ss and tt.

  1. Intercepts of Line gg:

    • x=0x = 0: Solve 3+s1=03 + s \cdot 1 = 0.
    • y=0y = 0: Solve 3+s1=03 + s \cdot 1 = 0.
    • z=0z = 0: Solve 4+s2=04 + s \cdot 2 = 0.
  2. Intercepts of Line hh:

    • x=0x = 0: Solve 2+t0=02 + t \cdot 0 = 0.
    • y=0y = 0: Solve 2+t1=02 + t \cdot 1 = 0.
    • z=0z = 0: Solve 3+t(1)=03 + t \cdot (-1) = 0.

After solving, plot these points to obtain a clear representation in the coordinate system.

Part (b): Prove Lines gg and hh are Skew

To show that lines gg and hh are skew, we need to check:

  1. If they are parallel (they aren’t if their direction vectors are not scalar multiples of each other).
  2. If they intersect by checking if a common solution exists for ss and tt when equating the parametric equations.

Parallel Check:

  • Direction vector of gg: (112)\begin{pmatrix} 1 \\ 1 \\ 2 \end{pmatrix}
  • Direction vector of hh: (011)\begin{pmatrix} 0 \\ 1 \\ -1 \end{pmatrix}

Since these vectors are not proportional, lines gg and hh are not parallel.

Intersection Check:

Set (3+s3+s4+2s)=(22+t3t)\begin{pmatrix} 3 + s \\ 3 + s \\ 4 + 2s \end{pmatrix} = \begin{pmatrix} 2 \\ 2 + t \\ 3 - t \end{pmatrix} and solve for ss and tt. If no solution exists, the lines are skew.

Would you like a detailed walkthrough of each calculation step?

Additional Related Questions

  1. How do you find the equation of a line passing through two points in space?
  2. What conditions make two lines in space parallel, intersecting, or skew?
  3. How can you find the shortest distance between two skew lines?
  4. What are the geometric interpretations of intercepts in 3D space?
  5. How do direction vectors affect the orientation of lines in 3D geometry?

Tip: Always start by examining direction vectors to quickly determine if lines are parallel in 3D geometry.

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Math Problem Analysis

Mathematical Concepts

Analytic Geometry
Vector Equations
Skew Lines

Formulas

Parametric form of a line: \( \vec{x} = \vec{a} + t \cdot \vec{b} \)
Determining intercepts with coordinate planes
Checking if lines are parallel or intersecting by solving for parameters

Theorems

Conditions for lines to be skew (non-parallel and non-intersecting)

Suitable Grade Level

Grades 11-12