Math Problem Statement

The graph of the position s of an object as a function of time t is given. For the intervals [0,10], [10,20], [20,30], and [30,40], determine whether the acceleration is negative, zero, or positive.

Solution

Let's analyze the graph and the statements to determine whether they are correct or not.

Understanding the Graph

The graph shows the position ss of an object as a function of time tt. The shape of the curve indicates the velocity (slope) and acceleration (concavity) over the given time intervals:

  1. Positive acceleration: The slope of the graph (velocity) is increasing.
  2. Negative acceleration: The slope of the graph (velocity) is decreasing.
  3. Zero acceleration: The slope of the graph (velocity) is constant (a straight line).

Interval Analysis

  • Interval [0,10]:
    The graph starts from rest (slope = 0) and then increases in slope (curving upward). This indicates positive acceleration, not negative as stated.

  • Interval [10,20]:
    The slope of the graph appears to be constant (straight line), which means zero acceleration. This statement is correct.

  • Interval [20,30]:
    The graph shows the slope increasing further (steeper upward curve), which indicates positive acceleration. This statement is correct.

  • Interval [30,40]:
    The slope continues to increase (steeper curve), which again indicates positive acceleration. This statement is correct.


Corrected Statements

  1. On the interval [0,10], the acceleration is positive (not negative).
  2. On the interval [10,20], the acceleration is zero. (Correct)
  3. On the interval [20,30], the acceleration is positive. (Correct)
  4. On the interval [30,40], the acceleration is positive. (Correct)

Final Summary

  • Statement 1: Incorrect → Should be positive acceleration.
  • Statement 2: Correct.
  • Statement 3: Correct.
  • Statement 4: Correct.

Let me know if you'd like further clarification or additional help!


Related Questions:

  1. How is acceleration determined from a position vs. time graph?
  2. What would the velocity graph look like for this position graph?
  3. How can we identify zero acceleration on a curve?
  4. What is the relationship between concavity and acceleration?
  5. How does velocity behave during positive and negative acceleration?

Tip: Always remember, acceleration corresponds to the concavity of the position-time graph: upward concave = positive acceleration, downward concave = negative acceleration.

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Math Problem Analysis

Mathematical Concepts

Kinematics
Position-Time Graph Analysis
Velocity and Acceleration

Formulas

Acceleration: a = dv/dt (rate of change of velocity)
Velocity: v = ds/dt (slope of position-time graph)

Theorems

Concavity of position-time graph indicates acceleration
Slope of the graph indicates velocity

Suitable Grade Level

High School (Grades 9-12)