Math Problem Statement

Belen draws a graph of g(x)=3|x+1| and writes the following statements.

Select the THREE statements that are correct. A.g(x) has a y-intercept at (0,3).

B.g(x) has one x-intercept at (−13, 0).

C.g(x) is decreasing over the interval ​​{x∣x<−13}.

D.g(x) has an axis of symmetry at x=−1.

E.g(x) has a minimum at (−1,0).

Solution

Let's analyze each statement about the function g(x)=3x+1g(x) = 3|x+1| carefully.

Step 1: Understanding the structure of the function

The function g(x)=3x+1g(x) = 3|x + 1| is an absolute value function, which creates a "V"-shaped graph. The graph will have two distinct parts: one part will be decreasing and the other increasing. The vertex occurs where the expression inside the absolute value is zero, i.e., at x=1x = -1.

Step 2: Analyze each statement

A. g(x)g(x) has a y-intercept at (0,3)(0, 3).

To find the y-intercept, we substitute x=0x = 0 into the function:

g(0)=30+1=3×1=3g(0) = 3|0 + 1| = 3 \times 1 = 3

Thus, the y-intercept is (0,3)(0, 3), so this statement is correct.

B. g(x)g(x) has one x-intercept at (13,0)(-13, 0).

To find the x-intercept, set g(x)=0g(x) = 0:

3x+1=0x+1=0x+1=0x=13|x + 1| = 0 \quad \Rightarrow \quad |x + 1| = 0 \quad \Rightarrow \quad x + 1 = 0 \quad \Rightarrow \quad x = -1

Thus, the x-intercept is at (1,0)(-1, 0), not (13,0)(-13, 0). Therefore, this statement is incorrect.

C. g(x)g(x) is decreasing over the interval {xx<13}\{x \mid x < -13\}.

The function g(x)=3x+1g(x) = 3|x+1| is decreasing for x<1x < -1 because for values less than 1-1, the slope of the absolute value function is

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Math Problem Analysis

Mathematical Concepts

Algebra
Absolute Value Functions

Formulas

g(x) = 3|x + 1|

Theorems

Properties of Absolute Value Functions

Suitable Grade Level

Grades 9-12