To analyze the given circuit and answer the questions, we'll follow these steps:

Step 1: Determine the Peak Voltage at the Secondary Side (V_peak_secondary)

Given:

• Source Voltage (V_rms_primary) = 220 Vrms
• Transformer Ratio = 25:6

The transformer ratio relates the primary side voltage to the secondary side voltage as follows:

$V_{rms_{secondary}} = V_{rms_{primary}} \times \left(\frac{\text{Turns Ratio (secondary:primary)}}{\text{Turns Ratio (primary:secondary)}}\right)$

$V_{rms_{secondary}} = 220 \times \left(\frac{6}{25}\right) = \frac{220 \times 6}{25} = 52.8 \text{ Vrms}$

To find the peak voltage at the secondary side:

$V_{peak_{secondary}} = V_{rms_{secondary}} \times \sqrt{2} = 52.8 \times \sqrt{2} \approx 52.8 \times 1.414 \approx 74.67 \text{ V}$

Answer for A: The Peak Voltage at the secondary side is approximately 74.67 V.

Step 2: Determine the RMS Value at the Secondary Side (V_rms_secondary)

We already calculated this in Step 1:

Answer for B: The RMS value at the secondary side is 52.8 Vrms.

Step 3: Determine the Value of All Your RL (Load Resistance, RL)

Given:

• The Load LED has a voltage drop of 1.6 V and a current of 1.8 mA.

To find the Load Resistance $R_L$:

$R_L = \frac{V_{LED}}{I_{LED}} = \frac{1.6 \text{ V}}{1.8 \text{ mA}} = \frac{1.6 \text{ V}}{0.0018 \text{ A}} \approx 888.89 \text{ ohms}$

Answer for C: The value of your RL (Load Resistance) is approximately 888.89 ohms.

Step 4: Determine the Current Running in Your RL (I_RL)

Given that the load resistance $R_L$ is already known, and assuming the output voltage at $R_L$ is the same as the peak voltage minus the voltage drop across the diode (assuming a silicon diode with a forward voltage of 0.7V):

The output voltage across $R_L$ is:

$V_{RL} = V_{peak_{secondary}} - V_{diode} = 74.67 \text{ V} - 0.7 \text{ V} \approx 73.97 \text{ V}$

The current through $R_L$ is:

$I_{RL} = \frac{V_{RL}}{R_L} = \frac{73.97 \text{ V}}{888.89 \text{ ohms}} \approx 83.25 \text{ mA}$

Answer for D: The current running in your RL is approximately 83.25 mA.

Step 5: Determine the Output Voltage of Your RL (V_RL)

The output voltage across the load resistance $R_L$ was calculated in Step 4:

Answer for E: The output voltage of your RL is approximately 73.97 V.

Summary of Answers

• A. Peak Voltage at the secondary side: 74.67 V
• B. RMS value at the secondary side: 52.8 Vrms
• C. Value of RL: 888.89 ohms
• D. Current running in RL: 83.25 mA
• E. Output Voltage of RL: 73.97 V

Would you like more details on any of these steps?

Here are some related questions you might explore:

1. How would the peak voltage change if the transformer ratio were different?
2. What would be the impact of a different load resistance on the current?
3. How does the capacitor acting as an open circuit influence the overall circuit?
4. What would happen if the diode had a higher forward voltage?
5. How would the use of a different type of diode affect the output?

Tip: When analyzing circuits with transformers, always start by determining the secondary voltage using the turns ratio, as it sets the foundation for further calculations.