Math Problem Statement

Analyze the function f(x) = x^2 / (x^2 - 1) and explore its domain, asymptotes, zeros, and behavior near vertical asymptotes.

Solution

The function given in the image is:

f(x)=x2x21.f(x) = \frac{x^2}{x^2 - 1}.

Let us analyze and solve some relevant properties of this function. Below are steps you might be interested in:

1. Domain of f(x)f(x):

The function is undefined when the denominator equals zero: x21=0    x2=1    x=±1.x^2 - 1 = 0 \implies x^2 = 1 \implies x = \pm 1. Thus, the domain of f(x)f(x) is: xR{1,1}.x \in \mathbb{R} \setminus \{-1, 1\}.

2. Asymptotes:

  • Vertical Asymptotes: Occur at points where the denominator is zero, i.e., x=±1x = \pm 1.
  • Horizontal Asymptote: For large values of xx (x|x| \to \infty): limxf(x)=limxx2x21=x2x2=1.\lim_{x \to \infty} f(x) = \lim_{x \to \infty} \frac{x^2}{x^2 - 1} = \frac{x^2}{x^2} = 1. Similarly, as xx \to -\infty, the result is the same: limxf(x)=1.\lim_{x \to -\infty} f(x) = 1. Thus, the horizontal asymptote is y=1y = 1.

3. Zeros of f(x)f(x):

To find zeros, set the numerator to zero: x2=0    x=0.x^2 = 0 \implies x = 0. Thus, f(x)f(x) has a zero at x=0x = 0.

4. Behavior Near Vertical Asymptotes:

To examine the behavior near x=1x = 1 and x=1x = -1:

  • As x1+x \to 1^+, f(x)+f(x) \to +\infty (denominator approaches 0 from positive side).
  • As x1x \to 1^-, f(x)f(x) \to -\infty.
  • Similarly, as x1+x \to -1^+, f(x)f(x) \to -\infty, and as x1x \to -1^-, f(x)+f(x) \to +\infty.

5. Graphical Sketch:

The function has:

  • A zero at x=0x = 0.
  • Vertical asymptotes at x=±1x = \pm 1.
  • Horizontal asymptote at y=1y = 1.

Would you like a graphical representation or deeper exploration of properties like intervals of increase/decrease, concavity, or further calculus-based analysis?


Here are 5 related questions to deepen understanding:

  1. What is the derivative of f(x)f(x), and what does it reveal about increasing/decreasing intervals?
  2. How does f(x)f(x) behave near x=0x = 0? What is its slope at this point?
  3. Can f(x)f(x) have oblique asymptotes, and why or why not?
  4. How would modifying the numerator to x3x^3 change the function's graph?
  5. What are the concavity and inflection points of f(x)f(x)?

Tip:

Always check for both vertical and horizontal asymptotes when analyzing rational functions—they provide key insights into the function's behavior!

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Math Problem Analysis

Mathematical Concepts

Rational Functions
Asymptotes
Domain
Zeros of Functions
Limits

Formulas

f(x) = x^2 / (x^2 - 1)
Vertical Asymptotes: x^2 - 1 = 0 → x = ±1
Horizontal Asymptote: lim (x → ±∞) f(x) = 1
Zero of Function: x^2 = 0 → x = 0

Theorems

Asymptote Theorem
Limit Theorem
Domain and Range Theorem

Suitable Grade Level

Grades 11-12