Math Problem Statement

f(x) = x^3+4x^2-5x+2

Solution

The function given is:

f(x)=x3+4x25x+2f(x) = x^3 + 4x^2 - 5x + 2

Key Steps for Analyzing this Function

  1. Finding Roots: Solve f(x)=0f(x) = 0 to find the x-intercepts or real roots.
  2. First Derivative: To analyze the behavior of f(x)f(x) (increasing or decreasing intervals and critical points), compute f(x)f'(x): f(x)=3x2+8x5f'(x) = 3x^2 + 8x - 5
  3. Second Derivative: To find concavity and inflection points, compute f(x)f''(x): f(x)=6x+8f''(x) = 6x + 8
  4. Finding Intervals of Concavity: Set f(x)=0f''(x) = 0 and solve for xx.
  5. End Behavior: Since this is a cubic function, as xx \to \infty, f(x)f(x) \to \infty and as xx \to -\infty, f(x)f(x) \to -\infty.

Would you like to go into the details of these steps, or do you have specific questions?


Related Questions

  1. What are the real roots of f(x)=x3+4x25x+2f(x) = x^3 + 4x^2 - 5x + 2?
  2. How do we find the critical points and classify them?
  3. What are the intervals where f(x)f(x) is concave up or concave down?
  4. How does the end behavior of f(x)f(x) relate to the degree and leading coefficient of the polynomial?
  5. How would we approximate the x-intercepts using numerical methods?

Tip: Remember, cubic functions have at least one real root and often change concavity at one point, which can be an inflection point.

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Math Problem Analysis

Mathematical Concepts

Algebra
Calculus
Polynomial Functions
Derivative Analysis
Concavity

Formulas

f(x) = x^3 + 4x^2 - 5x + 2
First derivative: f'(x) = 3x^2 + 8x - 5
Second derivative: f''(x) = 6x + 8

Theorems

Intermediate Value Theorem for finding roots
First Derivative Test for identifying increasing and decreasing intervals
Second Derivative Test for concavity and inflection points

Suitable Grade Level

Grades 11-12