Math Problem Statement

Each dimension of a square playground is increased by 5 meters. a) Draw a diagram of the situation. b) Find a simplified algebraic expression for the area of the new playground. c) Find a simplified algebraic expression for the increase in area.

Solution

Let's tackle each part of this question systematically:

Part a) Draw a diagram of the situation.

Since I cannot directly draw here, I'll describe what the diagram should look like:

  • Start by sketching a square to represent the original playground. Label each side of the square as ss, where ss is the length of each side.
  • Then, draw a larger square around the original one, representing the new playground after the dimensions are increased by 5 meters. Each side of this new square will now be s+5s + 5 meters.
  • Label the dimensions of the larger square as s+5s + 5.

Part b) Find a simplified algebraic expression for the area of the new playground.

  • The side length of the new square is s+5s + 5.
  • The area AnewA_{\text{new}} of a square is found using the formula Area=side2\text{Area} = \text{side}^2.

Thus, the area of the new playground is: Anew=(s+5)2A_{\text{new}} = (s + 5)^2 Expanding this expression: Anew=s2+10s+25A_{\text{new}} = s^2 + 10s + 25

Part c) Find a simplified algebraic expression for the increase in area.

The increase in area is the difference between the area of the new playground and the area of the original playground.

  • The area of the original playground is Aoriginal=s2A_{\text{original}} = s^2.
  • The increase in area ΔA\Delta A is: ΔA=AnewAoriginal=(s2+10s+25)s2\Delta A = A_{\text{new}} - A_{\text{original}} = (s^2 + 10s + 25) - s^2 Simplifying: ΔA=10s+25\Delta A = 10s + 25

Summary of answers:

  • a) Diagram: A square s×ss \times s expanded to a new square (s+5)×(s+5)(s+5) \times (s+5).
  • b) The area of the new playground: Anew=s2+10s+25A_{\text{new}} = s^2 + 10s + 25.
  • c) The increase in area: ΔA=10s+25\Delta A = 10s + 25.

Would you like further details on any part?


Here are 5 follow-up questions:

  1. How would the result change if the increase was 10 meters instead of 5 meters?
  2. How does the increase in area relate to the perimeter of the original square?
  3. What would happen to the area if the sides were decreased instead of increased by 5 meters?
  4. Can you derive a general formula for the increase in area if the side length is increased by any amount xx?
  5. How would the algebraic expressions change if the original playground were rectangular?

Tip: Whenever you're expanding binomials, use the distributive property carefully: (a+b)2=a2+2ab+b2(a+b)^2 = a^2 + 2ab + b^2.

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Math Problem Analysis

Mathematical Concepts

Algebra
Geometry

Formulas

Area of a square: A = side^2
Binomial expansion: (a+b)^2 = a^2 + 2ab + b^2

Theorems

Properties of squares
Expansion of binomials

Suitable Grade Level

Grades 7-9