The given expression asks for the sum of three fractions:

$\frac{x}{x+3} + \frac{3}{x+3} + \frac{2}{x+3}$

Since all three terms have the same denominator, $x + 3$, we can add the numerators directly:

$\frac{x}{x+3} + \frac{3}{x+3} + \frac{2}{x+3} = \frac{x + 3 + 2}{x+3}$

Now simplify the numerator:

$\frac{x + 3 + 2}{x+3} = \frac{x + 5}{x+3}$

Thus, the sum is:

$\frac{x + 5}{x+3}$

Would you like more details on any part of the solution or clarification?

Here are some related questions:

1. What happens if $x = -3$?
2. How do you add fractions with different denominators?
3. Can you simplify the resulting fraction further?
4. How do you multiply two algebraic fractions?
5. How would you find the derivative of this sum with respect to $x$?

Tip: When adding fractions, always check if the denominators are the same. If they are, combine the numerators directly.