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The problem asks you to add the fractions \( \frac{2}{7} + \frac{5}{6} \) and reduce the answer to its lowest terms.

To solve this, we follow these steps:

### Step 1: Find the least common denominator (LCD)
The denominators are 7 and 6. The least common denominator is the least common multiple (LCM) of 7 and 6. Since 7 and 6 have no common factors other than 1, the LCM is \( 7 \times 6 = 42 \).

### Step 2: Convert the fractions to have the LCD as the denominator
We now convert each fraction to have a denominator of 42.

- For \( \frac{2}{7} \), multiply both the numerator and denominator by 6:
  \[
  \frac{2}{7} = \frac{2 \times 6}{7 \times 6} = \frac{12}{42}
  \]

- For \( \frac{5}{6} \), multiply both the numerator and denominator by 7:
  \[
  \frac{5}{6} = \frac{5 \times 7}{6 \times 7} = \frac{35}{42}
  \]

### Step 3: Add the fractions
Now that the fractions have the same denominator, we can add the numerators:
\[
\frac{12}{42} + \frac{35}{42} = \frac{12 + 35}{42} = \frac{47}{42}
\]

### Step 4: Simplify the fraction
The fraction \( \frac{47}{42} \) is already in its simplest form since 47 and 42 have no common factors other than 1.

Thus, the final answer is:
\[
\frac{47}{42}
\]

Let me know if you have any questions or want more details! Here are some related questions:

1. How do you find the least common denominator (LCD) of two fractions?
2. Can you explain why fractions with different denominators need to be converted before adding?
3. How would you subtract fractions with different denominators?
4. How do you convert improper fractions to mixed numbers?
5. What is the difference between the least common multiple (LCM) and greatest common divisor (GCD)?

**Tip:** Always check if the fractions can be simplified after performing any addition or subtraction.

Add the fractions: 2/7 + 5/6 and reduce the answer to lowest terms.

Learn how to add the fractions 2/7 and 5/6. The solution involves finding the least common denominator, converting fractions, and simplifying to lowest terms. Suitable for students in Grades 6-7.

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