Math Problem Statement

Add (6 - i) + (-7 + 9i) and simplify the answer in the form a + bi.

Solution

The problem is to add two complex numbers: (6i)+(7+9i)(6 - i) + (-7 + 9i).

To add complex numbers, combine the real parts and the imaginary parts separately.

  1. Real part: 6+(7)=16 + (-7) = -1
  2. Imaginary part: i+9i=8i-i + 9i = 8i

So, the sum is: 1+8i-1 + 8i

Answer: 1+8i-1 + 8i

Would you like more details or have any questions about this solution?


Here are some additional related questions for further practice:

  1. How would you subtract two complex numbers, such as (4+3i)(2+5i)(4 + 3i) - (2 + 5i)?
  2. What is the modulus of a complex number like 1+8i-1 + 8i?
  3. How do you multiply two complex numbers, such as (2+i)×(34i)(2 + i) \times (3 - 4i)?
  4. How would you find the complex conjugate of a number like 1+8i-1 + 8i?
  5. How do you divide one complex number by another, for example, 6i2+i\frac{6 - i}{2 + i}?

Tip: When adding or subtracting complex numbers, always handle real and imaginary parts separately for simplicity.

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Math Problem Analysis

Mathematical Concepts

Complex Numbers
Addition of Complex Numbers

Formulas

(a + bi) + (c + di) = (a + c) + (b + d)i

Theorems

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Suitable Grade Level

Grades 9-10