The number line in the graph represents values between $-7$ and $7$. These points are marked as open circles, which means they are not included in the solution set. The goal is to write an absolute value inequality that describes this range.

The center point of this range is $0$, and the distance from $0$ to either endpoint is 7. Therefore, the inequality will be of the form:

$|x| < 7$

This inequality states that the distance of $x$ from 0 is less than 7, covering all values between $-7$ and $7$, but not including $-7$ and $7$ themselves (open circles).

Thus, the absolute value inequality for the given graph is:

$|x| < 7$

Would you like more details or have any questions?

Here are 5 related questions to expand on this:

1. How would the inequality change if the circles were closed instead of open?
2. Can absolute value inequalities also have solutions outside a range? What would that look like?
3. How do you solve an absolute value inequality like $|x - 3| > 5$?
4. What is the difference between $|x| < a$ and $|x| \leq a$ in terms of graphing on a number line?
5. How can you write compound inequalities without absolute values for cases like this?

Tip: Always remember that open circles on a number line represent strict inequalities ($<$ or $>$), while closed circles represent inclusive inequalities ($\leq$ or $\geq$).