We are given a function $f(x) = 3|3x - 2|$, and we are asked to find the values of the function under the following transformations: $f(a+h)$, $-f(a)$, and $f(-a)$.

1. $f(a+h)$

For this transformation, substitute $a+h$ into the original function in place of $x$:

$f(a+h) = 3|3(a+h) - 2|$

Now simplify the expression:

$f(a+h) = 3|3a + 3h - 2|$

2. $-f(a)$

For this transformation, we take the negative of $f(a)$. Start by substituting $a$ into the original function:

$f(a) = 3|3a - 2|$

Then, apply the negative:

$-f(a) = -3|3a - 2|$

3. $f(-a)$

For this transformation, substitute $-a$ into the original function in place of $x$:

[ f(-a) = 3|3(-a) - 2|