Math Problem Statement

If n = 480 and p̂ = 0.5, construct a 90% confidence interval about the population proportion. Round your answers to three decimal places.

Solution

Let's go through each part of the question step-by-step.

Given Data

  • Sample size (nn) = 480
  • Sample proportion (p^\hat{p}) = 0.5
  • Confidence level = 90%

Step-by-Step Solution

Part a: Is it safe to assume that n0.05n \leq 0.05 of all subjects in the population?

This question is asking whether the sample size is at most 5% of the population size. Generally, this assumption is valid when nn is a small portion of the total population. If the population is much larger than 480 (e.g., at least 9,600), then we can select "Yes."

Part b: Verify np^(1p^)10n\hat{p}(1 - \hat{p}) \geq 10.

Let's calculate: np^(1p^)=480×0.5×(10.5)=480×0.5×0.5=120n\hat{p}(1 - \hat{p}) = 480 \times 0.5 \times (1 - 0.5) = 480 \times 0.5 \times 0.5 = 120

Since 120 is greater than 10, this condition is satisfied. So, we enter 120.0 in the box.

Confidence Interval: Constructing the 90% Confidence Interval

The formula for a confidence interval for a population proportion is: p^±Zp^(1p^)n\hat{p} \pm Z \cdot \sqrt{\frac{\hat{p}(1 - \hat{p})}{n}}

  1. Determine ZZ for a 90% Confidence Level: For a 90% confidence level, the critical ZZ-value is approximately 1.645.

  2. Calculate the Margin of Error (ME): ME=1.6450.5×(10.5)480=1.6450.25480ME = 1.645 \cdot \sqrt{\frac{0.5 \times (1 - 0.5)}{480}} = 1.645 \cdot \sqrt{\frac{0.25}{480}} ME=1.6450.000520831.6450.02280.0375ME = 1.645 \cdot \sqrt{0.00052083} \approx 1.645 \cdot 0.0228 \approx 0.0375

  3. Calculate the Confidence Interval: p^ME=0.50.0375=0.4625\hat{p} - ME = 0.5 - 0.0375 = 0.4625 p^+ME=0.5+0.0375=0.5375\hat{p} + ME = 0.5 + 0.0375 = 0.5375

So, the 90% confidence interval for the population proportion is: 0.463<p<0.5380.463 < p < 0.538

Summary of Answers

  • a. Yes
  • b. np^(1p^)=120.0n\hat{p}(1 - \hat{p}) = 120.0
  • Confidence Interval: 0.463<p<0.5380.463 < p < 0.538

Would you like a detailed explanation of any specific part?

Related Questions

  1. What is the purpose of checking the condition np^(1p^)10n\hat{p}(1 - \hat{p}) \geq 10?
  2. How is the Z-value determined for different confidence levels?
  3. Why is it important to have a large enough sample size for confidence intervals?
  4. What does the margin of error represent in a confidence interval?
  5. How does increasing the confidence level affect the confidence interval width?

Tip

Always check conditions like sample size relative to population and np^(1p^)10n\hat{p}(1 - \hat{p}) \geq 10 to ensure the validity of a confidence interval for proportions.

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Math Problem Analysis

Mathematical Concepts

Statistics
Confidence Intervals
Population Proportion
Sample Size

Formulas

Confidence interval formula for population proportion: p̂ ± Z * √(p̂(1 - p̂) / n)
Sample proportion: p̂
Margin of error: Z * √(p̂(1 - p̂) / n)

Theorems

Central Limit Theorem (for large sample size and normal distribution approximation)
Z-score for confidence intervals

Suitable Grade Level

College-level Statistics