Math Problem Statement

Obtain a 90% confidence interval for the difference, μ1 - μ2, between the mean numbers of acute postoperative days in the hospital with the dynamic and static systems.

Solution

The image shows a problem related to the construction of a 90% confidence interval for the difference between the means of two independent samples (dynamic and static systems) in a nonpooled t-procedure.

Given Information:

  • Sample means:
    • xˉ1=7.00\bar{x}_1 = 7.00 (Dynamic system)
    • xˉ2=10.83\bar{x}_2 = 10.83 (Static system)
  • Sample standard deviations:
    • s1=1.71s_1 = 1.71
    • s2=3.97s_2 = 3.97
  • Sample sizes are not given directly, but we can deduce them from the table:
    • n1=8n_1 = 8 (Dynamic system)
    • n2=9n_2 = 9 (Static system)

Formula for the Confidence Interval:

The formula for the confidence interval for the difference between two independent means when using the nonpooled t-procedure is:

(xˉ1xˉ2)±tα/2×s12n1+s22n2(\bar{x}_1 - \bar{x}_2) \pm t_{\alpha/2} \times \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}}

Where:

  • tα/2t_{\alpha/2} is the critical value from the t-distribution, with degrees of freedom approximated using:

df=(s12n1+s22n2)2(s12n1)2n11+(s22n2)2n21df = \frac{\left(\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}\right)^2}{\frac{\left(\frac{s_1^2}{n_1}\right)^2}{n_1-1} + \frac{\left(\frac{s_2^2}{n_2}\right)^2}{n_2-1}}

Let's calculate the confidence interval step by step.The 90% confidence interval for the difference between the mean number of acute postoperative days in the hospital (dynamic system - static system) is approximately:

(6.440,1.220)(-6.440, -1.220)

This means we are 90% confident that the true difference between the means lies between -6.440 and -1.220.

The degrees of freedom used for this calculation is approximately 11.13.

Would you like more details or have any further questions?

Here are 5 related questions for further exploration:

  1. What does a negative confidence interval indicate about the difference between the two systems?
  2. How would the confidence interval change if the sample sizes were larger?
  3. How is the nonpooled t-procedure different from a pooled t-procedure?
  4. What would the confidence interval look like for a 95% confidence level?
  5. How does the margin of error relate to the width of the confidence interval?

Tip: Always check if the assumptions of the t-procedure (like normality and independence of samples) are met when interpreting results.

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Math Problem Analysis

Mathematical Concepts

Confidence Intervals
t-distribution
Statistics
Inferential Statistics

Formulas

(x̄1 - x̄2) ± t(α/2) × sqrt((s1^2 / n1) + (s2^2 / n2))
df = ((s1^2 / n1) + (s2^2 / n2))^2 / ((s1^2 / n1)^2 / (n1 - 1) + (s2^2 / n2)^2 / (n2 - 1))

Theorems

t-distribution Confidence Interval
Degrees of Freedom Approximation

Suitable Grade Level

College Level Statistics