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The image contains a mathematical problem written in Indonesian. Here's the translated text from the image:

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**Problem:**

Using the digits 0, 1, 2, 3, 4, 5, create a 3-digit number where no digits are repeated. How many such numbers can be arranged?

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### Interpretation:

We need to calculate how many distinct 3-digit numbers can be formed using the digits {0, 1, 2, 3, 4, 5}, without repetition of digits.

- The number cannot start with 0 because it must be a valid 3-digit number.
- The remaining digits can be any from the set.

#### Step-by-Step Solution:

1. **First digit**: There are 5 possible choices for the first digit (1, 2, 3, 4, 5). We exclude 0 as the first digit.
2. **Second digit**: After selecting the first digit, there are 5 digits left (including 0), so 5 possible choices.
3. **Third digit**: Once the first two digits are chosen, 4 digits remain, so there are 4 choices for the third digit.

Thus, the total number of 3-digit numbers is:

\[
5 \times 5 \times 4 = 100
\]

### Final Answer: 
There are **100 distinct 3-digit numbers** that can be formed.

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Let me know if you would like further clarification or details.

Here are 5 related questions for practice:

1. What if the number had to be 4 digits long instead of 3?
2. How many two-digit numbers can be made from the digits 0, 1, 2, 3, 4, 5 without repetition?
3. What if repetition of digits was allowed for the 3-digit number?
4. How many 3-digit numbers can be formed if the digits must be in ascending order?
5. Can you create a formula to generalize the number of n-digit numbers formed from a set of m digits?

**Tip**: When arranging digits, always pay attention to restrictions (e.g., first digit can't be 0, no repetition, etc.) as they significantly affect the calculation.

Using the digits 0, 1, 2, 3, 4, 5, create a 3-digit number where no digits are repeated. How many such numbers can be arranged?

Learn how to form 3-digit numbers from the digits 0, 1, 2, 3, 4, 5, where no digits repeat. This combinatorics problem involves calculating the number of permutations with step-by-step guidance. Suitable for students in Grades 6-8.

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