The image contains a mathematical problem written in Indonesian. Here's the translated text from the image:

Problem:

Using the digits 0, 1, 2, 3, 4, 5, create a 3-digit number where no digits are repeated. How many such numbers can be arranged?

Interpretation:

We need to calculate how many distinct 3-digit numbers can be formed using the digits {0, 1, 2, 3, 4, 5}, without repetition of digits.

• The number cannot start with 0 because it must be a valid 3-digit number.
• The remaining digits can be any from the set.

Step-by-Step Solution:

1. First digit: There are 5 possible choices for the first digit (1, 2, 3, 4, 5). We exclude 0 as the first digit.
2. Second digit: After selecting the first digit, there are 5 digits left (including 0), so 5 possible choices.
3. Third digit: Once the first two digits are chosen, 4 digits remain, so there are 4 choices for the third digit.

Thus, the total number of 3-digit numbers is:

$5 \times 5 \times 4 = 100$

Final Answer:

There are 100 distinct 3-digit numbers that can be formed.

Let me know if you would like further clarification or details.

Here are 5 related questions for practice:

1. What if the number had to be 4 digits long instead of 3?
2. How many two-digit numbers can be made from the digits 0, 1, 2, 3, 4, 5 without repetition?
3. What if repetition of digits was allowed for the 3-digit number?
4. How many 3-digit numbers can be formed if the digits must be in ascending order?
5. Can you create a formula to generalize the number of n-digit numbers formed from a set of m digits?

Tip: When arranging digits, always pay attention to restrictions (e.g., first digit can't be 0, no repetition, etc.) as they significantly affect the calculation.